Without multipole expansion

Home Forums Hyperfine course a nucleus with a general shape ? Without multipole expansion

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    Yens Elskens

    One of the things I see, is that we used part of the multipole expansion (the zeroth order) to complete the unperturbed Hamiltonian (the usual electron problem we solve for the hydrogen atom). As a result, our unperturbed system would’ve been unbound to begin with and our perturbation would not have been small compared to the unperturbed state.

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