Home Forums Hyperfine course a nucleus with a general shape ? Without multipole expansion

Viewing 1 post (of 1 total)
  • Author
    Posts
  • #3957
    Yens Elskens
    Participant

    One of the things I see, is that we used part of the multipole expansion (the zeroth order) to complete the unperturbed Hamiltonian (the usual electron problem we solve for the hydrogen atom). As a result, our unperturbed system would’ve been unbound to begin with and our perturbation would not have been small compared to the unperturbed state.

Viewing 1 post (of 1 total)
  • You must be logged in to reply to this topic.