Energy correction

Viewing 1 post (of 1 total)
  • Author
  • #4263
    Jef Morlion

    Yes even though there will be no Fermi contact contribution there will still be a Bohr-Weisskopf contribution due to the finite size of the nucleus. Although the electrons do not move into the nucleus they will result in a hyperfine field that is felt by the nucleus.

Viewing 1 post (of 1 total)
  • You must be logged in to reply to this topic.